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1-Point:
Vanishing point is identical with the projection center . Draw lines from cube edge to . The vanishing points of the cube diagonals are found by adding lines with distance to the projection center, parallel to the edges of the cube.

2-Point:
Vanishing points , lie on a line with the projection center . Given a cube edge , add connections from the end vertices to the vanishing points.
Now, consider shifting the upper corner of the cube into the projection center. Then, forms a right triangle with and , where is the footpoint of . Given the lengths , , we can construct the vanishing points of the diagonals of the cube.
and can be found geometrically by constructing a half circle above and intersecting it with the perpendicular above .

3-Point:
Only the three vanishing points are given. The projection center is found by intersecting the three heights of the triangle . Based on these heights, we again use Thales' theorem to find the right triangles above the edges of the vanishing point triangle. By intersecting the angle bisectors with the respective edges, the diagonal vanishing points are found.